If $\lambda$ is the length of the pipe, then the fundamental frequency corresponds to
$\begin{align*}\frac{\lambda}{4} = L\end{align*}$
The next lower wavelength will correspond to
$\begin{align*}\frac{3\lambda}{4} = L\end{align*}$
The wavelength is divided by $3$ , so the frequency is multiplied by $3$ , so the next higher frequency is
$\begin{align*}\left(131 \mbox{ Hz}\right) \cdot 3 = \boxed{393 \mbox{ Hz}}\end{align*}$
Therefore, answer (D) is correct.

Solution to 2008 Problem 47